其实 Python 中一般都是直接用 urllib.urlopen() 来抓取网页内容或者模拟登陆等操作，但是 GAE 出于安全考虑不可以用 urlopen 操作，取而代之的就是 urlfetch.fetch()。fetch() 函数、参数(via)：
fetch(url, payload=None, method=GET, headers={}, allow_truncated=False, follow_redirects=True, deadline=None)
Python语言: GAE urlfetch登录人人
01 def login_renren(self):
02 login_url = ‘http://passport.renren.com/PLogin.do’
03 login_data = urllib.urlencode(
04 {
05 ‘domain’:‘renren.com’,
06 ‘email’: renren_username,
07 ‘password’: renren_passwd,
08 ‘origURL’:‘http://home.renren.com/Home.do’,
09 })
10 result = urlfetch.fetch(
11 url = login_url,
12 payload = login_data,
13 method = urlfetch.POST,
14 headers = {‘Cookie’:make_cookie_header(cookie),
15 ‘Content-Type’:‘application/x-www-form-urlencoded’,
16 ‘User-Agent’:‘Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.2) Gecko/20100115 Firefox/3.6′ },
17 follow_redirects = False)
02 login_url = ‘http://passport.renren.com/PLogin.do’
03 login_data = urllib.urlencode(
04 {
05 ‘domain’:‘renren.com’,
06 ‘email’: renren_username,
07 ‘password’: renren_passwd,
08 ‘origURL’:‘http://home.renren.com/Home.do’,
09 })
10 result = urlfetch.fetch(
11 url = login_url,
12 payload = login_data,
13 method = urlfetch.POST,
14 headers = {‘Cookie’:make_cookie_header(cookie),
15 ‘Content-Type’:‘application/x-www-form-urlencoded’,
16 ‘User-Agent’:‘Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.2) Gecko/20100115 Firefox/3.6′ },
17 follow_redirects = False)
继续学习 GAE。
